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Image for Problem 5.15 Piles of snow on slippery roofs can become dangerous projectiles as they melt Consider a chunk of

Can someone please explain what the question is asking and what each part entails? The answers are above!

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Answer #1


m*g*sintheta = us*m*g*costheta


us = tantheta = tan27 = 0.51

---------------


m*g*d*sin27 - uk*m*g*d*cos27 = 0.5*m*v1^2


v1 = sqrt(2*g*d*(sin27 - uk*cos27))

v1 = 6.29 = 6.3 m/s

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energy conservation

0.5*m*v1^2 + m*g*h = 0.5*m*v2^2

v2 = sqrt(v1^2 +2*g*h)

v2 = sqrt((6.3*6.3)+(2*9.8*9)) 14.7 m/s = 15 m/s

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