Question

4) A parallel pole electromagnetic wave with a frequency of 10 kHz arrives from the air towards the ocean surface with an arrival angle of Fi (i) = (80 + m) °. Here, since the electrical properties of m = 2 and ocean water are ?? = 81, ?? = 1, ? = 4,
a) θt refraction angle, ? || Find the penetration coefficient and the ocean depth where the electric field intensity decreases by 30 dB.
b) If a perpendicular polar electromagnetic wave from a source below the ocean to the air came to the water-air interface with θi = 20 °; What would be the critical angle θc?

Yardımcı Bağıntılar 2n2 cos O T|| = n2 cos Ot+ ni cos i n2 cos Ot – ni cos i T|| E n2 cos Ot+ni cos Oi 2n2 cos O Ti= n2 cos Oi+ni cos Ot

Answer 1

@ Given that f = 10KHZ air ural, Er=1 oil ot a water Er=81 ural, 5=u given o i = 80tm = 80+2=820 by Snell's s law 81*1 simCOL) 181 sincot) g= sin(82) =) sinottoolt sincot Ot=sha Coll) = 6-3150 so sin ot = ooll

so cos ot= Vi-simot - Colo? osota 0.9939 and cosoi = cos(820) = 6.139 and Illa 2 nzusoi nzcusottni caso i n2= 12on un tj 120Kur for rzowe so n2= 120K - tj izok 81 81 n2= 1204 tj 120K g g tonal= n2= 1200 xr2 /uso g n2= 59.6 20 245 tll= 2x 59.20 Lus x onlog 59.20/48×0.993g+ (1200) Co-lag) Ill= 16-452450 58.83 2 45° + 52.3752 11.63 + J 16.31 = 16.45 Luso u 1-6 tj 416 +52.3752 93.9752tjuis THE 16-45/45° CO2.72423.870 Il = 0.16 L21.10° for roowe Wholtro wolle ZxX10 xuxx107x1x4 und 103 2

isod 20.397 Nelm 80 benetratim coeducient (6)=144 so lhe a 2.518 int we know that- E=Eo e -Lac given Els 30 dB below that to so - 30 = tog (6) 80 E=0.0316EO let at a=211 E²0-0316 Ebson -2 0-0316 70 % e → so 7221 Don (6616) = 43.454 9.39724 - 3.454 naa 8.7m 6 lay snell's to at otagoo and oi=oc so IX1 shnoc SlX1 Singoo sinoc=11920all) so Toca 6.3720 at ou = 200 total internal reflection will occur because ois oc. reflection Please like my solution