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Question 4 (16 Points) Use Nevilles method to approximate V11 with the following function and values. Use this polynomial to

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f(x) = 5x at x=1 Mo = 6, 2,38, X2=10,83 =12, 44=13 Po wayo Po, 1 (1) bu (a)=Y, Po, 2(X) bo, 3(a) Þl,2601 62220) zYz bigla) baboroC11) = yo = f(ad = f(6) 2.44949 bil (11) = f(x) = $18)= 2.828.43 Þ2,2 (11) = f(x) = f(0) = 3.16228 f(12) = 3.46410 bu,ucl$2,3() = (x2-x) $2,2(11) + CX-Xz) 53,3C1U X3-02 (12-10) [ 3.16228) + (11-10)[3.46410] 12-10 3,31319 , , (4) - ( 24-3) Ba, 30152,4(11) = [My-XJb2, 3(11) + (X-92] 53,4(117 14-02 -(13-11) (3.31319) +(11-101 ( 3.32265] 13-10 = 3: 31634 Þ0,3(01) = ( 13-23Þory (11) = (xy-) Þo, 3(11) at (0-20) 1,4(11) 24-70 (13-11) ( 3.3163745+ [11-6) (3.31668) 13-6 = 3.316 592 fia)= Ja at 11 is

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