Question

what will the new temperature be?

31 g of copper pellets are removed from a 300°C oven and immediately dropped into 80 mL of water at 25°C in an insulated cup.

what will the new water temperature be?*

Answer 1

solution! Explanation & Both the water and Copper will obtain the same temperaty same amount of heat that will be lost by copper and absorbed T4 aud by water. we know the fact that the sum of two heat energies must be the system is iso lated. Jero as net - Beoppen + @water =0, For Copper - o copper = m Copper e coppex (Tf - 3000°c (:7; = 300 given For water water = mwater X c water X (Tp-25) e (i = 25 give] From copper water. mcopper X Coopper XCTA-300) mwater x Cwater & Tf 25)

mCopper Tf (mcopper & Ccopper & munter X Gwater water water 825 +300 x mcoppe X C Copper XT f- - 300 xh copper & Eopper - nwatery Caterkar water* Gubater tf X X Ccopper mwater X Coater X 25 +300x copper & Ccopper THE mcopper & Ccopper + mwater & Cwater. where mwater density x volume =(1 7/md) (80 ml) = 0:08kg water = 4190 Jo kg) Ccopper = 385 To kq) m Copper = 0.031 substitute all values in above to formula, 0:08 X 4190 X25 +300 X 0.031.X 3853 = 34-450 0.03\X 385 +0:08 X 4190 Tf = 34.45 &