The solubility constant Ksp expression for Pb3(PO4)2 is DA. [Pb2+1[P0437 B. 6[Pb2+1[P0437 C. [Pb2+1/3[P04371/2 D. [Pb2+2[P04373...

Question

Question

science chemistry

Answer 1

Answer #1

Solubilty product Ksp of the given general reaction is given by,

A,Bb(s) =aAt (aq) + bB (aq) Ksp = [A+][B-]

Here,

Pb₃(PO₄)₂ -----> 3 Pb²⁺ + 2 PO₄^3-

So Ksp of Pb₃(PO₄)₂ is given by,

Ksp =[Pb²⁺]³[PO₄^3-]²

Option E is corrrect.

Answer 2

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