A number that is divisible only by 1 and itself is a prime
number.
For example: 2, 3, 5, 7, 11, 13 etc.
Note: 1 is neither prime nor a composite number.
Below are the steps to check whether a number is prime or not a
prime.
Step-1: Read the number and store it in the variable num.
Step-2: Call the function primeNum, by passing the
value. Check if the entered number is equal to 1(num==1), if so,
print the statement it is neither prime nor composite. If the
entered number is other than 1 use the for loop to check whether
the number is divisible by other number beginning, from i=2 to
num/2 (remember a number is prime if it is divisible by 1 and
itself, so i=2). Now use the if statement to check whether the
remainder is zero after dividing the number by i, if the remainder
is 0, return 0 to main function and print the number is not prime,
else return 1 and print the entered number is prime.
NoteL Please refer to the screenshot of the program for code indentation and explanation.
C program to check whether the entered number is prime or not.
#include<stdio.h>
int primeNum(int);
int main()
{
int num, res;
printf("Enter a number to check whether it is prime or not:
");
scanf("%d",&num);
res = primeNum(num);
if ( res == 1 )
printf(" %d is a prime number.", num);
else if(res==0)
printf("\n %d is not a prime number", num);
return 0;
}
/*Function to check whether a number is prime or not. If prime
returns 1, else returns 0 */
int primeNum(int num)
{
int i;
if(num==1)
{
printf(" 1 is neither prime nor a composite number
");
}
else
{
for ( i = 2 ; i <= num/2 ; i++ )
{
if ( num%i == 0 )
return 0;
}
return 1;
}
}
The screenshot of the complete program along with the explanation and output is shown below:

Output-1:

Output-2:

Output-3:

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