Question

time is 0 with an initial ccw angular velocity of w0 = 0.5 rad/sec. The bar shown is rotating around a fixed point O with an angular acceleration a=k/w^4 with the constant k = 150 sec^-6 (units are rad/sec^2)

once the bar reaches an angular velocity of w=5 rad/sec counterclock wise, the angular displacement of the bar from its initial angular position is approximately

time t which the bar is rotating with an angular velocity of w= 5 rad/sec CCW

velocity of point A(Va) at time t = 0 sec is

y. o x 10 in 3 in А 8 in Figure 3.4

Answer 1

0 Given angular velocity at t=0, Wo= 0.5 rad /sec Velocity Of A at t=0 10 NA = WOXOA ) From AOA'A OA= Von Trin =11073)782 15.2643 in "VA = 0.5X15-2043 VA = 7.6322 in/sec) at t=0 sec

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