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Question 33 (8 points) A 28.7 mL sample of KOH required 31.3 mL of 0.118 M H2SO3 to neutralize it. How many grams of KOH were
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Gruen 28.7mL KOM Зmek, 2KOH + H₂SO3 K₂SO3 +2160 d KOH (Imole 12803 31.3ml g 0.118 M H2SO3 tylos Nojmoles: Molarity & Volume =d

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