Question

Ni = 6, N2 = 36. Write a Matlab program calculating; N2 A= (1/11)N1eN Hi=N1 1b- f(x) = ln (12) L3 N1 [x3*N1 N2/(cos(N1)]

Answer 1

1.)

• The Expression A is a summation expression.
• We can calculate this by with and without for loop, we will do both.

using for loop:

• Set A = 0
• loop for i = N1 to N2
• add  (1/factorial(N1))^N1*exp(N1) to A

program:

N1 = 6;

N2 = 36;

A = 0;

for i = N1:N2

A = A+ (1/factorial(N1))^N1*exp(N1);

end

disp(A)

output:

N1 = 6; N2 = 36; A = 0; for i = N1: N2 A = A+ (1/factorial (N1)) ^Nl*exp(N1); end disp(A) 8.9770e-14

without for loop:

• A can be given as A =(N2-N1+1)*(1/factorial(N1))^N1*exp(N1), That is , the summation expression multiplied by N2-N1+1

program:

N1 = 6;

N2 = 36;

A =(N2-N1+1)*(1/factorial(N1))^N1*exp(N1);

disp(A)

output:

Ni 6; 36; N2 = (N2-N1+1)* (1/factorial (N1)) ^Nl *exp(N1); disp (A) 8.9770e-14

1b)

• Define a function handle f to calculate f(x)
• Then substituate any value for x to obtain a result.

program:

N1 = 6;

N2 = 36;

f = @(x)log(N1/12)*(x.^(3*N1)*exp(N2/cos(N1)));

x = -10:0.01:10;

plot(x,f(x));

xlabel("x");

ylabel("y");

title("x vs. f(x)")

grid on;

outputs

0 x vs. f(x) x1043 -2 -4 у 09 -10 -12 -14 -10 -5 5 10 0 х