Question

Question 10 1 pts Problem 10: Interpolation, least squares, and finite difference Consider the following data table: CON 2 = 0 0.2 0.4 0.6 f(t) = 2 2.018 2.104 2.306 If the Sum of the Squares of the errors for the linear least-squares fit for the above problem is computed as SSE = 8.579 x 10-3 and the sum of the squares of the deviation from their mean is computed as SS, = 0.059, then the R2 value for the linear least fit and the standard error Sxy are R2 -3.55 and Sxy-1.72 None of the above. R2 -1.85 and Sxy=0.06 R2 -0.85 and Sxy-0.05 R2 -0.90 and Sxy-0.05

Answer 1

Answer: None of the above

$R^2=1-\frac{SSE}{SS_0}$

$R^2=1-\frac{8.579*10^{-3}}{0.059}$

$R^2=1-0.15$

$R^2=0.85$

$S_{xy}=\sqrt{\frac{SSE}{n-2}}$

$S_{xy}=\sqrt{\frac{8.579*10^{-3}}{4-2}}$

$S_{xy}=0.06$