Question

answer those Question please?

QUESTION 1 A ray of light traveling in air strikes a boundary at an angle of 75.7 degrees to the normal. After crossing the boundary, the ray travels at an angle of 26.1 degrees to the normal. What is the speed of light in meters per second in the second medium? (The answer should be given in scientific notation with two digits right of the decimal, for example, 1.23e+5 means 1.23 times 10 to the 5th power. Do not include unit in answer.) QUESTION 2 You take an object that is 15.1 cm high and place it 34.5 cm in front of a diverging lens which has a focal length of -102 mm. What will be the size of the image in centimeters? (State answer with 2 digits right of decimal and use negative sign if image is inverted Do not confuse cm and mm Do not include unit in answer)

Answer 1

1) sin(r)/sin(i)=v2/v1

i=angle of incidence=75.7

r=angle of refraction=26.1

v1=velocity of light in air=3Xm/s

105

v2=velocity of light in given medium=?

sin(r)/sin(i)=v2/v1

v2=v1X[sin(r)/sin(i)]=3X
105
X[sin26.1/sin75.7]=1.36X
105
m/s=1.36X
105
=speed of light in second medium

2) (1/u)+(1/v)=1/f

u=object distance=34.5cm

v=image distance=?

f=focal length=-102mm=-10.2cm

(1/u)+(1/v)=1/f

(1/34.5)+(1/v)=1/(-10.2)

1/v=(-1/10.2)-(1/34.5)

v=-(34.5X10.2)/(-34.5-10.2)=-7.87cm=7.87cm (value)

magnification   m=hi/ho=v/u

hi=image height=?

ho=object height=15.1cm

hi/ho=v/u

hi=vXho/u=7.87X15.1/34.5=3.45cm=3.45