Question

can someone help me with this physics Lab Vibrating String Experiment I'm confused please and thank you

Vibrating String Experiment Objective To study the factors affecting the velocity of waves in a stretched string. Apparatus Linear transducer, function generator, string, meter stick, mass set, table clamp with pulley. Optional: strobe light.

I have This data for the four-time I did the Experience

Answer 1

ve represents the velocity of wave in string. Mi represents Line mass density. in string. ł represents the tension observation uz Young V (ms) Mig/m) (mykg) 4.5 45 XIO 8370.42 91.49 1 0-22 2.272 XIOU 4034.79 63.52 2 0.44 2010-62 I'll XIOU 44.82 3. 0.9 0.54X10U 1007:43 4 . 1.84 31.74 Here, I have taken the reciprocal af u and multiplied by 108 to convert the grom in to Ка:

1100 8000 u? 12 (m/s) 4000 5 A 1000 4 I 2 You (m/kg) [x 109 have we let's measure 1 the slope four paints of each paint with respect to origin slobe cut A = (VA-0) = -1007:43 (Yua o 0:54X103 ~ 1.8 656 Kg m/s² o Slobe at B - 201062 Toll 8103 210811 kg m/s2

slope at c= 4034.73 2.272x103 1.7758 kg mis? slope at DE 8 370.42 4.545 XION 1.842 kg m/8? Average slobe - 1.811 +1.805 6+1.7758 + 1.842 4 1.828 6 kgm/s² Now, coming to the Pension "P" in the string mg = (200x1053 kg) & 9.8 moy = 0.2% 9.8 kgm/82 1.96 kg m/8? Hence from 1 and Average slope ~ Tension Islope = T (iv) 2 i.ee,

In case of any doubt please comment below.