Question

What is the potential difference across the battery if the emfis 10.8 Volts? 10.0Ω 4.00 Ω 5.00 Ω -ΑΜ- 2.00 Ω 3.00 Ω r= 1.0 Ω emf Answer: What is the power (in Watts) in the 5.0 a resistor if the emf in the battery is 11.9 Volts? 10.0Ω 4.00 Ω 5.00 Ω 2.00 Ω - 3.00 Ω ΑΛΛ r= 1.0 Ώ wΗ

Answer 1

first of all we try to calculate the total external resistance using series and parrallel resistnace.internal resitance is in tge series with external resiatnace.then simple apply ohms law to calculate current through circuit.and in the last voltage diference
Case-1. of all calculate total Resti Resistance of Crocent on ML un Mme Internal Resistance tu 32 Awwww th riin on ish Step: Two Pasrallel Resistance dor - Ri= 1085 10 +5 3 so in series 42 2 Step 2 RI R = R,+2 20 +4 = 22 e Now 38 are parnelled Step3 22 h, & 3 22,03 3 66 31 هی X3 R3 = c 31 04+3 66 h 2 ar are in series 1282 Step 4 - Now 31 66 +2 31 R 31 31 This is total external Resistance R = 128 R=498 M 11 E

Now &= ICR++) 128 31 10.8 = I (5.129) 2.1056 Amp, I= 10.8 5.129 - E-I8 Potential differen = 10.8-2.1056 va 8.7V 11.9W for é = Case-2 E = I (R+2) 11,9 = I 5.129 2.32 I=2.32 Amp, Potential difference V = &-Ir - 11.9 - v= 9.5&m