Question

PLEASE SOLVE QUESTION 2.

1. Plot absorbance Vs time curves for each tube on the same graph paper. You should get 5 curves on the same graph paper. Use different color for each line. Attached your graphs to your lab report. 2. Determine VO for each line corresponding to each tube (Draw a tangent to each of the graph and find out the slope of your tangent. This slope gives you Habsorbance/ Itime, that is the rate of formation of the product/ initial rate of the reaction/ initial velocity of the enzyme). Time elapsed/sec spectrophotometric reading tube spectrophotometric reading tube2 spectrophotometric reading tube spectrophotometric reading tube spectrophotometric reading tubes 20 0.011013458 0.076880835 0.142384614 0.207527798 0.272313356 40 0.022026917 0.153761669 0.284769227 0.415055596 0.544626713 60 0.033040375 0.230642504 0.427153841 0.622583393 0.816940069 80 0.044053834 0.307523339 0.569538455 0.830111191 1.099253426 100 O.OSS067292 0.384404174 0.711923068 0.9 1.361566782 120 0.066080751 0.4609 0.854307682 1.058 140 0.077094209 0.5348 0.994 1.218 160 0.088107668 0.608 0.96 180 0.09882 0.6822 1.044 200 0.1068 0.74 1.04 Chart Title 1.S 0.5 0 50 100 150 200 250 spectrophotometric reading tubel-spectrophotometric reading tube2 spectrophotometric reading tube3-spectrophotometric reading tube --spectrophotometric reading tubes

Answer 1

Ans 2: As given in the question that the tangent or the slope of each graph gives us the intial rate of the reaction which we have to calculate here. So by using excel i am plotting the 5 graphs are enclosing them below:

So from all the graphs and the respective equations of the slope, we get:

Initial rate of the reaction for tube 1 = 0.0005 concentration/sec.

Initial rate of the reaction for tube 2 = 0.0037 concentration/sec.

Initial rate of the reaction for tube 2 = 0.0053 concentration/sec.

Initial rate of the reaction for tube 2 = 0.0082 concentration/sec.

Initial rate of the reaction for tube 2 = 0.0136 concentration/sec.