Question

A 50% confidence level has a confidence interval of 0.6745. A 90% confidence level has a confidence interval of 1.96. A 99% confidence level has a confidence interval of 2.57. A critical distance is measured 17 times. The mean is 317.6 feet, the sample standard deviation is 0.46 feet. The standard error of the mean value with a confidence level of 90% is (A) (2.57) (0.46) 17 (B) (1.96) (0.46) 17 D. (1.96) (0.46) V17 (D) (0.46) (17) 1.96

Answer 1

The standard error of the mean value is given as:

$SE = Z\frac{ \sigma }{ \sqrt[]{n}}$

where

Z = confidence interval,

$\sigma =$ standard deviation,

n = number of samples.

According to the given question,

Z (for 90% confidence level) = 1.96

$\sigma =$ 0.46 feet

n = 17

Hence,

$SE = \frac{(1.96)*(0.46)}{\sqrt{}17}$