Homework Answers
pOH = 12.05
Explanation
Given : initial concentration of aspirin = 0.426 M
Ka = 3.0 x 10^-4
| ICE table | HC9H7O4 (aq) |  |
H+ (aq) | C9H7O4- (aq) |
| Initial conc. | 0.426 M | 0 | 0 | |
| Change | -x | +x | +x | |
| Equilibrium conc. | 0.426 M - x | +x | +x |
Ka = [H+]eq[C9H7O4-]eq / [HC9H7O4]eq
3.0 x 10^-4 = [(x) * (x)] / (0.426 M - x)
Solving for x, x = 0.01116 M
[H+] = x = 0.01116 M
pH = -log[H+]
pH = -log(0.01116 M)
pH = 1.95
pOH = 14 - pH
pOH = 14 - 1.95
pOH = 12.05
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