Question

F p Questions: Use the source table shown below to answer questions 1 to 4. Source SS df MS Subjects 323 19 Treatment 72 4 18 Error 76 3 Total 623 99 6 < 0.05 228 1. Identify which type of ANOVA (Repeated-Measures or Factorial) was used to generate this source table, and explain how you determined your response. [1 mark] 2. Would the results of this test significant at a=0.05? How do you know this? [1 mark] 3. Would the results of this test significant at a=0.01? How do you know this? [1 mark] 4. [Let's play pretend!] Oops! The professor made a mistake! He was supposed to run a between- subjects ANOVA instead of the one conducted above. How could you correct this mistake using the data given in the source table? [1 mark] Use the source table shown below to answer questions 5 to 7. Source SS df MS Colour (C) 28 2 14 Type (T) 8 2 4 CXT 40 4 10 Error 162 81 2 Total 238 89 F 7 2 5 p < 0.01 > 0.05 < 0.01 5. Assuming this is an independent design, how many groups of subjects would be used in this study, and how many subjects would be in each group? Explain your response (and show the necessary calculations). [1 mark] 6. What do we know about the interaction between “Colour” and “Type" in this study? [1 mark] 7. Think carefully! Does the independent variable “Type” have any significant effect on the dependent variable in this study? Explain your response. [1 mark]

Answer 1

1. This is a Repeated measure ANOVA because there are subjects and treatments.

2. The results are significant at $\alpha$ = 0.05 since the p-value is less than 0.05.

3. We cannot say if the results are significant at $\alpha$ = 0.01 since we do not have the exact p-value.

4. We would combine the subject's effect with the error term.

5. Groups of subjects of C = 2 + 1 = 3

Groups of subjects of T = 2 + 1 = 3

Number of subjects for every group = 90/3 = 30

6. There is a significant interaction between T and C since the p-value < 0.01.

7. Since the p-value > 0.05 for T, there is no significant effect of Type.