Thin layer chromatography was performed on an unknown substance. The substance separated into two spots: A...
Thin layer chromatography was performed on an unknown substance. The substance separated into two spots: A AND B. Spot A travelled 3.85 cm and Spot B travelled 5.98cm. The colvent travelled 7.54 cm.
1.) Which of the two components (A or B) was more attracted to the stationary phase? Explain
2.) Calculate the Rf and of A and B. (show work)
3.) An analysis on an unknown showed one spot with an Rf of 0.52. Which component was the unknown, A or B? Explain.
Homework Answers
1.
Spot A traveled 3.85 cm.
Spot B traveled 5.98 cm.
The spot that traveled the lower distance among the two spots was more attracted to the stationary phase. Hence, the component A was more attracted to the stationary phase.
2.
Distance that solvent front traveled = 7.54 cm
Rf of A = distance traveled by spot A/distance traveled by solvent
= 3.85 cm / 7.54 cm
= 0.51
Rf of B = distance traveled by spot B/distance traveled by solvent
= 5.98 cm / 7.54 cm
= 0.79
3.
Analysis on an unknown showed one spot with an Rf of 0.52 which matches with the Rf (0.51) of component A. Hence, the component A was the unknown.
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