Question

Thanks in advance

Provide a MATLAB code to express the position of a moving particle as a function of time x = [(t - 15)/100 + 1] sin (3 t) y = [(t - 15)/100 + 1] cos (0.8 t) z = 0.4 t^(3/2)

Answer 1

Write the MATLAB code to plot the position of the particle for 0≤ t ≤ 30 %Start of script

%Create a vector 't' from 0 to 30 in steps of 0.01. t=0:0.01:30;

%Create a vector with given function.

x=(((t-15)/100)+1).*sin (3*t);

%Create a vector with given function.

y=(((t-15)/100)+1).*cos(0.8*t);

%Create a vector 'z' with given function.

z=0.4*t.^(3/2);

%Plot the position of particle as function of time plot3(x,y,z,’b’,’linewidth',1)

%labels the x-axis of the current axes

xlabeI('\fontname{Times New Roman}\itx,'FontSize',12); %labels the y-axis of the current axes

ylabeI('\fontname{Times New Roman}\ity,'FontSize',12); %labels the z-axis of the current axes

zlabel(‘\fontname{Times New Roman}\itz,'FontSize',12); %Add title to the plot

title('Position of the moving particle as a function of time'); %Enable the grid in the plot

grid on

%End of the script