Question

Important industrial processes, such as converting iron ore to iron and then to steel, involve coupling a non-spontaneous reaction, such as reducing Fe₂O₃ (iron ore)to metallic iron, with a spontaneous process such as the oxidation of carbon in CO to CO₂:

Fe₂O₃ (s) + 3 CO (g)  2 Fe (s) + 3 CO₂ (g)

Reagent	ΔHºf (kJ/mol)	ΔSº(J/mol*K)
Fe2O3 (s)	-824.2	87.4
CO (g)	-110.5	197.7
Fe(s)	0	27.3
CO2 (g)	-393.5	213.8

1. Use the thermodynamic data provided above to determine if this reaction is endothermic or exothermic under standard conditions (298 K). Show your work!
2. Is the reaction spontaneous under standard conditions?  Show your work!
3. Calculate the value of the equilibrium constant, K_p, at 298 K using the value of ΔGº_rxn you obtained in part b. (If you did not find the value of ΔGº_rxn in part b, you may assume ΔGº_rxn = -25.0 kJ/mol.)
4. If the reaction was performed under non-standard conditions at 200 ºC, using 6.0 g Fe₂O₃, 0.245 atm CO, and 0.175 atm CO₂what is ΔG_rxn and is the reaction spontaneous?

Show work please stuck on this homework problem

Answer 1

FG 03 (s) + 32010) -+ 2Fe (s) + 300219) Hnen = (4H) Product - (H) memutant = 2414)re(s) + 3 (04)60,ce) – (H)F6,0360) – 3 (Menca) = 2X0 + 3x(+393.5) – (-824.2) – 3*(-11005) E-1180:5 + 824.2 + 331,5 4H = -24.8 kJ ... The CH of the reaction is live, so exothermic, Now, as - (as Jendes, -as meae tant 52X(as) Fe +3(015),19) – (45) Fe205= 3 (95)cola) :=(2x 27-3) +(3x 213-8)– (87-4) -(3x 197-7) = 15.5 J/K the temperature = 208K Here 8 X 15 4 G2 = 9H - TIS =(-24.8x103) – (298x15.5), < - 29919 J so the oG of the reaction is negative. so it is spontaneous meaction o Now, Goorn ==RT enke Here, Gonxoni = -25.0KB/mol = -25X10?J/mol T= 298 K GAAT

cit25.0X103J/mol =48.314 Ji'mori ! x298 K enkp enke 25*103 8.314x298 enkp=10.09 [Rp = 2:41x104 / Any O G = = RT enkp+ RT en Qp Qp = activity quotiant. Fe2O2 (s) + 3 Colg) -> Fe(s) + 3C0219) : .: Rp = file Hore, Peo = 0.175 atm beo = 0.245 atm mm @ (0:175) 0.17513 (0.24513 . 5 0. 3644 ..46 = RT en ) dG = RT en ( 0.3614404) : AG=(the The AG of the reaction ere, so the reaction is spontanious.