Homework Answers
Initial vertical speed of ball = 19.6 m/s
Acceleration = 9.8 m/s^2 downwards
(a)
At max altitude , Final velocity = 0
V = u + a*t
0 = 19.6 - 9.8 *t
t = 2s
Time taken by ball to reach max altitude t =
2s
(b)
V^2 = u^2 - 2*g*h
0 = 19.6^2 - 2*9.8*h
h = 19.6^2 / (2*9.8)
h = 19.6 m
Max altitude h = 19.6 m
(c)
At t =1
V = u - gt
V = 19.6 - 9.8 *1
V = 9.6 m/s
Velocity V = 9.6 m/s upwards
Acceleration = 9.8 m/s^2 downwards
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