The following code on a 32 bit machine:
int x= 0xAABBCCDD;
print("%02x",(int) (* ((char *)(& x))&0xFF))
will print out a ___________________ if the machine is big-end-in.
Answer:
will print out a ________AA___________ if the
machine is big-end-in.
Explanation: 0x AABBCCDD will be stored as
DD CC BB AA In the memory As Big Endian and when we do . & FF,
Then last two bytes will be be the answer
Thanks, PLEASE UPVOTE
The following code on a 32 bit machine: int x= 0xAABBCCDD; print("%02x",(int) (* ((char *)(& x))&0xFF))...
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