Question

Hydrogen is the only element whose energy levels can be expressed exactly in an equation. Calculate the ratio (lambda E/ lambda F) of the wavelengths of the transitions labeled E and F in problem 2 on p. 1026. Express your answer as an exact fraction, not a decimal approximation. In an experiment in which atomic wavelengths are being measured, this ratio provides a natural, stringent check on the precision of the results.

n=4 n=3 GH n=2 DEF n=1 ABC

Answer 1

We know that ( 누 Rul ( for transition E:- hi 2. 4 2 ; cs T 매 ㅗ 1 (주) 2 42 매 한 ( 4년 심 = Rn ( - ( ) [ce = 뵮 TE o) 16. 3.RM and for transition F:- My RH ( 1 / 1 T E 1 s2 ) ) ( ㅗ 2s CSS canned with Cam Scanner

25 -4 100 DER auten An 21 100 те loo 21 и les 16 16x21 sy - BRM 100/1kn 300 TE de = 2x91 cel = 447 2S 28 XE XF 28 u 2 S Ausser CScanned with CamScanner