Question

Consider the function f(x)=3−6x2,  −4≤x≤2f(x)=3-6x2,  -4≤x≤2.

The absolute maximum value is:
and this occurs at: x=

The absolute minimum value is:
and this occurs at: x=

Answer 1

foc) = 3-6x² -4EX L2 3. f(x) = 3-6x? [-4,2) sia) = -122 critical point falls EO) -12x50=0 ало of "x) = -12 So f"(0) = -1270 hence xeo is point тах іmе. So absolute maximum value f(o) = 3 Occurs at X=0 Also 11 -93 f(-4) = of (2) - 3-6(-4)? = 3 - 6x6 3-612) = 3-6X4 = -2/ (6 absolute minimum value f(-4)= -93 occurs at x = -4.