Question

Problem 1: Shear Lag Factor & Effective Areas For the steel tension members and corresponding connections shown below, determine the effective area. Note that the abbreviation PL indicates a steel plate with naming convention: thickness x width. Assume standard diameter holes, where applicable a) For each case, compute or determine the shear lag factor, the net area, and the effective area. Tabulate your final answers lowest values? What do these values mean in terms of the stresses at the connection? S"- PL3/s × 4 2"22" 2" Weld Weld /s-in.-diam. bolts 3A-in.-diam. bolts \ weld

Answer 1

"a) NET AREA, AN = GROSS AREA = 5.9 in^2 LENGTH OF CONNECTION, R = 5 degree x^vector = 1.47 therefore SHEAR LAG FALOR, U = 1 -x^vector/ 2 = 0.706 therefore EFFECTIVE AREA, A_2 = UAn = 4.165 in^2 b) An = AG = 4 times 3/4 = 3 in^2 L = 5^inch W = 4 "" L > W therefore U = 0.75 [case 4 (c)] therefore A_2 = UAn = 2.25 in^2 c) An = Ag = 5/8 times 5 = 3.125 in^2 U = 1 [case 1] therefore An = UAn = 8.125 in^2 d) Ag = 1/2 times 5 1/ 2 = 2.75 in^2 db = 3/4 in therefore dn = 3 /4 + 1/8 = 0.875 in AN = Ag -dn times t = 2.75 -0.875 times 1/2 = 2.3125 in^2 U = 1 [Case -1] "