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2. For the capacitor network shown below, the potential difference across ab is 35.0 V. Find: (a) the total capacitance of th
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6.2 18 HH 3.5 8 4.8 HE a 3.0805 6.2 - . الى 4 & le= 8.6448 - 3:0805} 8.6*4.8 3.0805 - 8- 6+4 8 3.5 7 b § Ceq = 62* 11.8 - 4.0Au between 0 and 6 will be O=AUxc AUF - 76.616 – 10.12850 7.5644 Now We ham 62 11.8. 35 se 315 10.1285 u some K AU= 10.1285 f

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