Consider the two adjacent blocks shown in the figure below. A
horizontal external force, F, is applied rightward to the small
block on the left. The horizontal surface on which the blocks slide
is frictionless. If M = 1.0 kg and F = 16.7 N, determine magnitude
of the force applied by the small block onto the large block.

The net force acting on both the blocks is
F = Mt a
Where Mt is the total mass of the system.
Mt = 4M + 1 M = 5 M
The total force F = 16.7 N
We can find the acceleration as
a = F / Mt
a = 16.7 N / 5 kg
a = 3.34 m/s2
This is the net acceleration of the system.
We can then find the force acting on the 4M mass by the small mass
as we know the acceleration of the system
F4M = 4M x a = 4 kg x 3.34 m/s2
F4M = 13.36 N
Consider the two adjacent blocks shown in the figure below. A horizontal external force, F, is...
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