Homework Answers
Its given that,
Battery Voltage = Vb = 9 volts ; R1 = 15 Ohm and R2 = 23 Ohm ;
L = 0.46 Henry ; V(L) at t = 0.008 seconds
1/Req = 1/R1 + 1/R2 = 1/15 + 1/23
Req = 9.08 Ohm
time constant = L/R = 0.46 / 9.08 = 0.0506
we know that, Voltage across an inductor at time t is given by
V(L) = Vb e-tR/L
V(L) = 9 x e-0.008/0.0506
V(L) = 0.854 Volts
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