Question
Please solve 1, and 2
problems: approximately + Each problem is divided into several (related or unrelated) parts. Circle our answers. This is a 50 minute test. Please do not use red ink or write each problem is worth 12 points (UNLESS OTHERWISE DESIGNATED uu eHis Cest. There are the boxes next to the problem numbers. ProbLem I Rank the following data set: (8 pts. Multiplication: /-Divi sioni pi 9,16,7,4,16,9,8,6,6,41,9,13,5,16,4,18,9,15,16,4 ANALYSIS of VARIANCE IE the nulI hypothesis is rejected in, Use the Scheffe test when the sample sizes are unequal to test the differences between the means and the Tukey test when the sample sizes are equal. Perform the following steps. a) State the hypotheses and identify the claim. b) Find the critical value. c) Compute the test value. d) Make the decision. The expenditures (in dollars) per pupil for states in three l sections of the country are listed. Using a0.05, can lone conclude that there is a difterence in means? (16 pts.) Middle third Western third Bastern thi 4946 5953 6202 7243 6113 6149 7451 6000 6479 5282 8605 6528 6911 a difference in mean QUESTION-ND herc wester n 27 ,3 ?? Middle 36, 437
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Answer #1

Problem Amatura ok Varia miadle 2299 1 4 1 궈s Sa53 6.202 6 +1 6113 373686 2x32二192322 2 sy = g336 2. 13 Burmo log 3S232 SST=problem 2: a) Null hypothesis: There is no significant difference in mean of three states.

b) Critical value:: at alpha 0.05 from the table of F at degree of freedom 2 and 10 is 4.10.

c) True Value: 0.6484 calculated.

d) we accept the null hypothesis. as 0.6484 < 4.10. We accept the null hypothesis.

Problem 1 is the incomplete question, the upper part of the question is not visible.

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