Part B
Use the formula C_{1}V_{1} =C_{2}V_{2}
Where, C_{1} = initial concentration = 31.5 %
V_{1} = initial volume = 0.644 L = 644 ml
C_{2} = final concentration = 24.8 %
V_{2} = final volume = ?
C_{1}V_{1} =C_{2}V_{2} Thus,
V_{2} = C_{1}V_{1} /C_{2}
Substitute value in above equation
V_{2} = 31.5 644 / 24.8 = 818 ml
final volume = 818 ml
Part C
Use the formula C_{1}V_{1} = C_{2}V_{2}
Where C_{1} = initial concentration = ?
V_{1} = initial volume = 510 ml
C_{2} = final concentration = 6.00M
V_{2} = final volume = 1.34 L = 1340 ml
Substitute the value in formula
C_{1}V_{1} = C_{2}V_{2}
C_{1} = C_{2}V_{2}/V_{1}
= 6.00 1340 / 510 = 15.76
C_{1} = 15.76 M
initial concentration of NaCl = 15.76 M
To understand how to prepare a dilute solution and determine the concentration or volume of the...
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