

QUESTION 4 Evaluate the double integral. 6x2 - 3y) da, where R = [(x, y)/05 x...
6. (4 pts) Consider the double
integral∫R(x2+y)dA=∫10∫y−y(x2+y)dxdy+∫√21∫√2−y2−√2−y2(x2+y)dxdy.(a)
Sketch the region of integration R in Figure 3.(b) By completing
the limits and integrand, set up (without evaluating) the integral
in polar coordinates.
2 1 2 X -2 FIGURE 3. Figure for Problem 6. 6. (4 pts) Consider the double integral V2 2-y2 (2? + y) dA= (32 + y) dx dy + (x2 + y) dx dy. 2-y? (a) ketch the region of integration R in Figure 3. (b) By completing...
1. Use polar coordinates to evaluate the double integral dA z2 +y where R is the region in the first quadrant bounded by the graphs x = 0, y = 1, y=4, and y V3z.
1. Use polar coordinates to evaluate the double integral dA z2 +y where R is the region in the first quadrant bounded by the graphs x = 0, y = 1, y=4, and y V3z.
10 Given the double integral 4(x+ y)e dy dx, where R is the triangle in the xy-plane with vertices at (-1, 1), (1, 1) and (O,0). Transform this integral into J g(u.)dv du by the transformations given by 스叱制一想ル r}(u+v), y (u + v), y =-(u-v). Then, Evaluate the integral." (u-v). Then, Evaluate the integral. r
10 Given the double integral 4(x+ y)e dy dx, where R is the triangle in the xy-plane with vertices at (-1, 1), (1, 1)...
5. Evaluate the integral c (2x -y)dx + (x + 3y)dy along the path C: line segment from (0,0) to (3,0) and (3,0) to (3,3)
5. Evaluate the integral c (2x -y)dx + (x + 3y)dy along the path C: line segment from (0,0) to (3,0) and (3,0) to (3,3)
Calculate the double integral ||(x + 3 y) dA where R is bounded by y = Vx and y = x
Use the transformation u = 3x + y, v=x + 3y to evaluate the given integral for the region R bounded by the lines y = - 3x + 1, y= - 3x + 3, y= - = X, and y=- -x + 2. ne lines y = – 3x+1, y = – 3x+3, y=-3x, and y=-**+2. 3 Siſ(3?+ 16 +3%) dx ay SJ (3x? + 10x9 +35) dx dy=0 (Simplify your answer.)
Evaluate the double integral || f(x, y) dA over the region D. JU f(x, y) = 6x + 9y and D = {(x, y)SXS 1, x3 sy s x3 + 1}
reverse the order of integration and evaluate : double integral e^y^2 dy dx and dy=from 2x to 2 and dx= is from 0 to 1. please explain how you reverse it, and show me all the steps in the evaluation of the new integral
Evaluate the integral Sf. 313x + 3y dA where the region R is given by the figure with a = 3 and b = 5. (Assume the curved boundary of the figure is circular with center at the origin.) S IR ŽV3x2 + 3y2 dA = (125sqrt(3)/2)tan^(-1)(3/4)
Evaluate the double integral ∫∫D x cos y dA, where D is bounded by x = 0, y = x², and x = 3 Answer: