Question

important don't use arrays or listed pleaseeeee

in python 3 Write a program that given a collection of ?N numbers will find the largest value, its frequency and the average of the ?N numbers.

• Get the value of ?N from the user.

• If ?≤0N≤0, display an appropriate error message and terminate the program; otherwise

• Read the values as entered from the user. (If ?=5N=5, then there are 5 values the user is going to enter).

• Find the largest, its frequency (how many times it is repeated) and the average of these ?N values.

• Hint: To find the largest value, read the first value before the loop then assume that this first value entered by the user is the largest value. Within the loop compare the assumed largest value with other values read inside the loop and change the largest value accordingly.

  Sample Runs Enter how many values to consider: -2 Wrong input. Input must be > 0 Enter how many values to consider: 4 Enter value 1: -3 Enter value 2: -10 Enter value 3: -7 Enter value 4: -3 Maximum value= -3 It's frequency is 2 Average = -5.75 Enter how many values to consider: 7 Enter value 1: 4 Enter value 2: 3 Enter value 3: 2 Enter value 4: 1 Enter value 5: 2 Enter value 6: 3 Enter value 7: 5 Maximum value= 5 It's frequency is 1 Average 2.86 =

Answer 1

Hello there. I hope you are fine.

Here is the Python code you need.

# import exit function
# we will use this to exit if user enters value of N less than 0
from sys import exit

# ask the user how many values to consider
N = int(input('Enter how many values to consider: '))

# check if N is less than 1
if N < 1:
    # if it is, print the message and exit with exit code 1
    print('Wrong input. Input must be > 0')
    exit(1)

# if N is not less than 1
# ask the user the very first value out of N values
num = int(input('Enter value 1: '))

# initialize maximum with the currently entered value
maximum = num

# initialize count to be 1
# assuming the currently entered number is the maximum
count = 1

# initialize total to be equal to num
# we will add to total in every iteration of for loop
# this is done to calculate average
total = num

# ask the remaining values from the user
for i in range(1, N):
    # get the input in input_num
    input_num = int(input('Enter value %d: ' % (i + 1)))
    # add it to total
    total += input_num
    # check if input_num is more than current maximum
    # if it is, set maximum to input_num
    # and set count to 1
    if input_num > maximum:
        maximum = input_num
        count = 1
    # if input_num is equal to maximum
    # increment count by 1
    elif input_num == maximum:
        count += 1

# calculate average
# it will be total divided by N (total values considered)
average = total / N

# print the maximum value
print('Maximum value = %d' % maximum)
# print its count
print("It's frequency is %d" % count)
# print the average, rounded to 2 decimal places
print('Average = %.2f' % average)

code snapshot:

from sys import exit N = int(input('Enter how many values to consider: ')) if N < 1: print('Wrong input. Input must be > 0') exit(1) num = int(input('Enter value 1: ')) maximum = num count = 1 total = num % (i + 1))) for i in range(1, N): input_num = int(input('Enter value %d: total += input_num if input_num > maximum: maximum = input_num count = 1 elif input_num == maximum: count += 1 average = total / N print("Maximum value %d' % maximum) print("It's frequency is %d" % count) print('Average %.2f' % average)

output:


Enter how many values to consider: -2 Wrong input. Input must be > 0

Enter how many values to consider: 4 Enter value 1: -3 Enter value 2: -10 Enter value 3: -7 Enter value 4: -3 Maximum value = -3 It's frequency is 2 Average = -5.75

Enter how many values to consider: 7 Enter value 1: 4 Enter value 2: 3 Enter value 3: 2 Enter value 4: 1 Enter value 5: 2 Enter value 6: 3 Enter value 7: 5 Maximum value = 5 It's frequency is 1 Average = 2.86

Feel free to open them in new tab if required.

Please read the comments to understand the code. I have tried my best to explain what each and every line does. If you still have any doubt or want me to change something, get back to me in the comment section below. I would love to help you out.

I hope this helps.

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