Question

2. By die Internation meth (10 ) JA

Answer 1

$\small Centroid \: on\: \, the\: x-axis,\: \overline{x}=\frac{\int xdA}{\int dA}$

yo 1-y=5 (1 da HE- w dA=ydn = (in - x²) da [dA=(5x-x²) d x] > we need to find the intersection of these curves. Oily = sa (i)y = -2 > point of intersection, n=n² n=24 n4n=0 R(23_1)=0 23-1 = 0 23=1 [n=1 is the point of intersection. (entroid on a anis (n. Inda] (da= (n - x²) da I Jan = f'(x - 2²) dx = {' (2²_22) dn > +

- -[-] = } - $ = 5 -> Jmda = f** (v2 – x) dx = [ (054 - 23) Ix - 3 = 5(2%-x²) da OM 3 - = Inda = 3 --07 - = B 3/20 n-Unda -= 0.45 da. 1/3 C=0:45

$\small Centroid \: on\: \, the\: x-axis,\: \overline{x}=0.45$