Question

PLEASE ANSWER ALL QUESTIONS

Problem 3: Equivalent Impedance, KCL, Curret Division. Consider the circuit in Figure 2Figure 1 i(t) aC v(t) cos(2π100x1 03t) 2 iL (t) R2 = 4 kQ, L = 3 mH, and C = 1 nF. Figure 2. Circuit for Equivalent Impedance Question 1 Question 6 Question 11 Real part of Zab [Ohms Phase of vit) [deg it) (leads or lags) iLit) by positive 0 21 O 22.5 O 25.2 O 112 degrees Question7 Question 2 Amplitude of i L(t) mA) Imaginary part of Zab [Ohms] Question 12 i-Lit) (leads or lags t) by positive degrees Question 8 021 O 22.5 030 ○ 25.2 Question 3 Phase of i Lit) [deg] Amplitude of ilt) [mA) Question 9 3 pts Question 4 i(t) (leads or lags) į-Lit) by positive phase angle Phase of ilt) Idegl O leads O lags Question 10 3 pts Question 5 i Lit) (leads or lags) Kt) by positive phase angle Amplitude of vit) V O keads O lags

Answer 1