Three small objects are located in the x-y plane as shown in the figure. The objects...

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science physics

Answer 1

Answer #1

Given, m_A = 1.93 kg, m_B= 2.09 kg, m_C = 3.67 kg

x =5 m, y = 4 m

The moment of inertai of each ball, I_A = m_A [(x-2)² + (y-2)²]

I_A = 1.93 [(5 - 2)² + (4 - 1)²] = 1.93 [9 + 9]

I_A = 34.74 Kg.m²

For the ball B

I_B = 2.09 * [(5 -7)² +(4 - 4)²] = 2.09 [4 + 0]

I_B = 8.36 Kg.m²

For the bal C

I_C = 3.67 [(5 - 5)² + (4-7)²] = 3.67 [0 + 9]

I_C = 33.03 Kg.m²

The total moment of inertia = 34.74 + 8.36 + 33.03

= 76.3 Kg.m²

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Answer 2

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