Question

Your stock cell concentration after couting your cells is 2 x 10^6 cell/ml. What volume of...

Your stock cell concentration after couting your cells is 2 x 10^6 cell/ml. What volume of cell suspension contains 200,000 cells?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Answer:

Cell concentration after couting cells is C1 -----> 2 x 10^6 cell/ml

Volume is V1 ----> 1ml

Volume of cell suspension V2?

When concentration is C2 -----> 200,000 cells or 2 x 10^5 cells

C1V1 = C2V2

V2 = [2 X 10^6 * 1ml]/[2 X 10^5]

V2 = 10ml (volume of cell suspension contains 200,000 cells)

Add a comment
Know the answer?
Add Answer to:
Your stock cell concentration after couting your cells is 2 x 10^6 cell/ml. What volume of...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • You calculated the live cell concentration to be 1.5 x 10^6 cells/mL. what is the volume...

    You calculated the live cell concentration to be 1.5 x 10^6 cells/mL. what is the volume of cell suspension needed to seed a T-75 flask with 7.5 x 10^5 cells in 10 mLs of media.

  • Your cell suspension is 6.3 x 10^8 cells /mL. Explain how to prepare a tube of...

    Your cell suspension is 6.3 x 10^8 cells /mL. Explain how to prepare a tube of 1 mL with cells at 2 x 10^5 cells/mL. Pipetting less than 1 μL is hard to do accurately. Do a dilution if less than 1μL After dilution,Now that you have your tube of 1 mL with cells at 2 x 10^5/mL, explain how to add 10^4 cells to each of 10 wells. Do you have enough cells?

  • you have a 2 ml solution of CHO cells at a concentration of 5.6 x 10^4...

    you have a 2 ml solution of CHO cells at a concentration of 5.6 x 10^4 cells/mL and need to produce a solution of 56 cells/mL set up detailed serial dilution given 8mL of 4.1 x10^3 cells/ML and need approximitly 100 cells/mL. set up detailed serial dilution by determining the aliquot to be transfered (v1) from the solution to get 100 cells/mL in a final volume of 10 mL given 10mL cell suspension of NIH cells at 3.8 x10^5 cells/ML...

  • 1. You have a bacterial cell culture with a concentration of 1x109 cells/ml. You need to...

    1. You have a bacterial cell culture with a concentration of 1x109 cells/ml. You need to dilute the cells to a concentration of 1x103. What is the correct ratio for this dilution? 2. You add 0.1 ml of a yeast culture to a test tube that contains 9.9 ml of buffer solution. What is the dilution factor of this mixture? 3. In a 1000 µl total dilution volume, the volume of cell culture used is 800 µl. What is the...

  • 1a Your cell suspension is 6.3 x 10^8 cells /mL. Explain how to prepare a tube...

    1a Your cell suspension is 6.3 x 10^8 cells /mL. Explain how to prepare a tube of 1 mL with cells at 2 x 10^5 cells/mL. 1b Now that you have your tube of 1 mL with cells at 2 x 10^5/mL, explain how to add 10^4 cells to each of 10 wells. Do you have enough cells?

  • You started with a cell count of 5.2 times 10^5 cells in a total volume of...

    You started with a cell count of 5.2 times 10^5 cells in a total volume of 3ml. You need lo seed a six-well plate with the following numbers. Calculate the volume of cell suspension you will need to transfer into 1 well. Each letter represents a different scenario. a. 1.2 times 10^4 cells/mL and up to 2 mL/well b. 2.5 times 10^5 cells/well and up to 2 mL/well c. 3 times 10^4 cells/well and up to 2 mL/well

  • Cells are kept in suspension in RPMI a media for glowing cells. You have 30 mL...

    Cells are kept in suspension in RPMI a media for glowing cells. You have 30 mL of a cell suspension at a concentration of 7.2 times 10^6 cells/mL. You need to dilute a portion of these cells such that 100 mu L of the new suspension will deliver 1 times 10^5 cells when plated in the wells of a 96-well microstate plate. How would you dilute some cells so you could prepare 48 such wells? Your answer should account for...

  • A total volume of 1 mL of cell suspension was used for this exercise. Blood was...

    A total volume of 1 mL of cell suspension was used for this exercise. Blood was diluted 1/10. The cells were then serially diluted using saline. -How was 1/10 cell suspension made? -How was 1/100 cell suspension made? -What is the difference between a 1/100 and 1/1000 cell suspension?

  • If you have a stock culture of bacteria at a concentration of 5*10 cells/ml, how much...

    If you have a stock culture of bacteria at a concentration of 5*10 cells/ml, how much stock cuiture and how much media would you add to obtain a final concentration of 2.5*10 cells/ml in a final volume of 20mL? (1 point)

  • For your experiment, you prepared 2ml of cells with a concentration of 2x106/ml (Tube F). You...

    For your experiment, you prepared 2ml of cells with a concentration of 2x106/ml (Tube F). You would like to use this cell's solution to prepare a 7ml flask (Tube G) of cells with a concentration of 5x105cells/ml. What volume in microliters of cell solution will you take from tube F into tube G?

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT