Question

To create X-rays, a strong electric field is placed between an anode and a cathode. Electrons are then disconnected from the cathode and accelerated toward the anode. When they enter the anode, X-rays are created. In this case, the cathode is placed in x = 0, and the anode in x-90 cm. The voltage between them is Uka-90 kV. You can assume that the electric field is homogeneous. Create a vector that contains 10 different values along the x-axis, x [0 10 20 30 40 50 60 70 80 90] cm. Thus, the first point is in the cathode and the other in the anode. Then calculate the electrical potential U = [U1 U2 U10] in the ten points. Use the unit V, and let the potential be zero at the cathode.

Answer 1

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Then Homogenous Electric field = V/R = 90 kv/90cm E Vector = 100k v/m then Electric field work on anode to cathode (because E Vector have direction on high potential to low potential) u_1 = E Vector times R_1 = 100 k times 0 = 0 v u_2 = E Vectors times R_2 = 100k times 10 cm = 10000 v u_3 = E Vectors times R_3 = 100k times 20 cm = 20000 v u_4 = E Vectors times R_4 = 100k times 30 cm = 30000 v u_5 = E Vectors times R_5 = 100k times 40 cm = 40000 v u_6 = E Vectors times R_6 = 100k times 50 cm = 50000 v u_7 = E Vectors times R_7 = 100k times 60 cm = 60000 v u_8 = E Vectors times R_8 = 100k times 70 cm = 70000 v u_9 = E Vectors times R_9 = 100k times 80 cm = 80000 v u_10 = E Vectors times R_10 = 100k times 90 cm = 90000 v }