
Can someone explain this question for me?
I understand I have to find an action potential, Q value and use a Nernst equation, but I can not actually apply those into a question.
Thanks

To To
Can someone explain this question for me? I understand I have to find an action potential,...
Can someone please tell me if I did the equations right and if the
anode and cathode reactions are correct .
Report sheet Exp. 11 Electrochemistry Date: Name: Partner's Name: Lab Section Anode Equation for the Cathode Equation for the Cathode Cell Ecell Reaction Anode Reaction oxidahon) Measured Cu-Zn MO Cu-Fe Zn-Mg M9 Fe-Mg Mg 2n
This is the third time I've
posted this question. Can someone please help me with the top one.
I slipped in a similar example. And the answer is not 2.4135
Consider the following cell reaction Fe(s)2 H ? M)-Fe2(100 M) +H>(g\1.00 atm) If the cell potential at 298 K is 0.307 volts, what is the pH of the hydrogen electrode? pH Consider the following cell reaction Ni(s)2 H (? M) Ni(100 M)Hg100 atm) If the cell potential at 298 K...
Could someone help me? I
slipped in a previous example for reference
Consider the following cell reaction: Fe(s) + 2 H+(?M —Fe2+(1.00 M)+H gX1.00 atm) If the cell potential at 298 K is 0.307 volts, what is the pH of the hydrogen electrode? pH= Consider the following cell reaction: Ni(s) + 2 H (?M) —+NI+(1.00 M)+H(E)1.00 atm) If the cell potential at 298 K is 0.104 volts, what is the pH of the hydrogen electrode? pH - 1.75 x Incorrect...
This is all the information I was given to answer this
question.
To determine the formation constant, Kf, for [Zn(CN)4)2-(aq), 4.00 mL of 1.50 mol/L KCN(aq) and 1.00 mL of 0.0750 mol/L Zn(NO3)2(aq) were combined. The mixture was stirred for 10 minutes to ensure that equilibrium had been reached. A voltaic cell was constructed to determine the concentration of uncomplexed Zn2+ (aq) ions left in solution at the end of the complexation reaction. The [Zn(CN)4]- (aq), Zn2+ (aq), CN (aq)...
Can someone please help me out
with this problem? If possible could you add steps so that I can be
able to do the rest on my own? Thank YOUUUU!!
A chemist designs a galvanic cell that uses these two half-reactions: half-reaction standard reduction potential N (9)+4H2O(1)+4e → N H (aq)+4 OH (aq) Ered = -1.16 V Zn²+ (aq)+2e → Zn(s) Exped=-0.763 V Answer the following questions about this cell. Write a balanced equation for the half-reaction that happens at...
how
would you go about solving this problem via using equations
just looking for the equation order i should go about solving this
problem
In this experiment you will be using the two half reactions Cu?"/Cu and Zn2 /Zn. The standard electrode potential, E°, for these half reactions is +0.34V and-0.76V respectively, so the Nernst Equation for these half reactions is the following Cu ea)+2e - Cus) E - 0.34V 0.0592V Cu2+] 0.0592V Zn 2 Note that solids by definition...
Can
someone please help me answering this question part a and b.
3. The value of E' for the following reaction is 0.189 V. a. What is the value of Ece given the concentrations shown? 4H) + Fe(s) + NO, 10) ► Fel) + NO + 2 H20 H: 0.1 M, NO,: 0.6 M, Fel: 1.0 M, NO: 0.5 M b. Draw a diagram of the cell, indicating the anode, cathode and electron flow through the salt bridge.
I dont understand what the nernst equations is so i dont know how to solve this question. Under what conditions is the Nernst equation used to calculate cell potential voltages in a voltaic cell? A. non-standard concentration only B. non-spontaneous reactions only C. reactions at equilibrium only D. the reaction of ions with the same charge only
Can someone show me the steps to derive carother equation and explain to me the process or what it is? I am confused with what it is and how to apply it. Thanks!
Chem 1212 Lab Report on electrochemistry
Electrochemistry When electrons transfer between reaction components in a redox reaction, we can harness the motion of the electrons to create a potential. Electrochemistry revolves around the separation of the two half-reactions in a redox reaction and establishing two different electrodes. This might involve physically separating the half-reactions or including a separator, such as a semi-permeable membrane or plastic dividers. With the reactions separated, the electrons will need to flow through the wire connecting...