Question

When 10.58 g H., react by the following balanced equation, 32.8g H., O are formed. What is the percent yield of the reaction? 2 Η., (g) + 0,(9) + 2 Η., Ο (1) Select the correct answer below: - Ο 32.2% Ο 34.7% Ο 65.3% Ο 38.9%

Answer 1

2 H2 (9) + O, (9) -- 2H2010) 2 moles of H₂ produce - 2 moles of H₂O Imole of the will produce 2 = 1 mole of the the reaction the actual yield should be of Imole of H₂O. so for - formation hiren: 10.58g of Hz 32.89 HO moles of H₂ = mass of H2 1 molar mass of 2 molar mass of H₂= 2gl male moles = 10.58 = 5.29 Moles of H₂O = mass of H₂o molar mass of ho molar mass of tho = 1891mal - moles= 22.8 = 19822 Here 5.29 moles of the form 1.822 moles of Heo 22 moles of theo 347 0.344 moles of Ho -1.822 Imole of H₂ will fosm 5.29 toined vild xloo - Vield obtained yield... % 0.347x100 Hethal yield m IX.00 = 34.77. ② is correct AnsE