Question 15 10 points Save Answer In a titration, a sample of HCl required 18.4 mL...

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Question 15 10 points Save Answer In a titration, a sample of HCl required 18.4 mL of a 0.7971 M NaOH solution to reach the e

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Answer 1

Answer #1

Molarity=moles of solute/volume of solution in litre

Molarity of NaOH = 0.7971M

Volume of solution=18.4ml = 18.4/1000 lit.

=1.84*10-2 L

So, moles of NaOH= molarity*volume

=0.7971*1.84*10-2.

=1.467*10-2

Hope you will like my answer.

Answer 2

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