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600 4. Chapter 10: Example Problem 10.3 (30 points, 10 points each) Using the isothermal transformation diagram for an iron-c
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esort srout 40€ + 360°ct 300 F 25014 sila) 4 bainite ab i martensite Meat Hubo TMF 3 Lot I Os 10 c 4 pearlite & bamite Scanne

Ok we tried mapping the processes on TTT diagram .

For part a). We can see the it is cooled to 350°C and it is still completely austenite and thenit is hold for 10000s , during which it crosses to Bainite region implies it transforms to Bainite completely and then quenched . So it will have Bainite (100%)

For part b) we can see it is cooled to 250°C and then hold for 100 s during which no transformation acts and it remains as austenite . After this it is coooled to room temp , thus it cuts martensitic start and finish line , implies it converts to martensite (100%)

For part c) we can see it is cooled at 650°C and hold for 20s , in this pearlite transformation is started but not completed as it doesn't cut pearlite finish line and then it is cooled to 400°C and then hold for 1000s , during which remaining austenite converts to Bainite as it cuts bainite finish line and then cooled to room temp.

So it contains pearlite and bainite mixture as final product.

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