The second minimum in the diffraction pattern of a 0.12 mm-wide slit occurs at 0.70 degrees....

Question

Question

The second minimum in the diffraction pattern of a 0.12 mm-wide slit occurs at 0.70 degrees. What is the wavelength of the light? answer in nm.

science physics

Answer 1

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Answer #1

Given that

m=2

slit width d = 0.12 mm

= 0.12 x 10^-3 m

angle θ = 0.70 degrees

The condition for the minimum in the diffraction is

d sinθ = mλ

λ = (d sinθ) /m

= ((0.12 x 10^-3m)sinθ)/m

= 733 x 10-9m

= 733 nm

Answer 2

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