We need to prepare 1X concentration from 10X buffer. Total volume is 20 µl.
So, N1V1 = N2V2
V1 = 20*1/10 = 2 µl
Volume of 10X buffer need to be added is 2µl.
We have 500 ng in 1 µl. Required is 1 µg. So, 2µl of DNA sample volume is needed.
We have 20 units restriction enzyme per µl and we need 20 units. So, required enzyme volume is 1 µl
Rest of the volume is water = total volume – volume of 10X buffer to be added – volume of DNA sample to be added – volume of enzyme to be added
Then, volume of water to pipet = 20-2-2-1 =15 µl of water
ure March, 24 Name: Lab Section: MoBio Chapter 7 Problem Set Homework Assignment #3 Final Cone...