Question

A stream of liquid cyclopentane flows at a rate of 0.35 lb_m / s into an initially empty container with a volume of 2.0 ft³, placed on a scale calibrated to read weight in lb_f. The process takes place at sea level.

When only the empty container was on the scale, the scale reading was 2.50 lb_f. Estimate the reading 10 seconds after the flow starts.

Answer is 6. I don't understand each step. Thank you!

Answer 1

Page No Date Mass Liquid flowrate (m) = 16m 0.35 1 s = 2.5 lot Inital weight of conture Time of frow = without liquid 10 seconds In 10 seconds, Amount of liquid in container Mass flowrate & 0.35 x 10 = time 16m x gee = sec = 3.5 IG Unit conversion 1 from lbm lom = to IGT is 1 16m given as " Amount of liquid in container = 3.5 lbm = 3.5 167 [ 166m = 11617 i Total weight alt 10 seconds = Initial weight of contoure & I Amount of cuquid l in contaurer after 10 secs / 2.5 + 3.5 - Gint 6 165 CANS As