Question

Name: PART II: USE THE COMPUTER Problem (40 points) A A tree cat = = A) Write a C++ program to reproduce the drawing below called (treeCat) using two user defined functions (UDE) called tree and cat treeCat + + + + B) The programmer needs to enter a positive integer for massive reproduction of the picture called treeCat. Expend your program to allow the user to reproduce the picture based on the following conditions: 1) 10 pictures on the same line if the entry is even. 2) 20 pictures on the same column if the entry is odd.

Answer 1

Hey!

Answer for the first part is below. I am giving the code as well as a screenshot of the output.

Code for A)

// Program begins from here

#include <iostream>
using namespace std;

// user defined function to print tree
void tree(){
   cout << "   *   " << endl;
   cout << " *** " << endl;
   cout << " ***** " << endl;
   cout << "*******" << endl;
   cout << " *** " << endl;
}
// user defined function to print cat
void cat(){
   cout << "/\\   /\\ " << endl;
   cout << " o o   " << endl;
   cout << " =   = " << endl;
   cout << " ---   " << endl;
}

int main(){
   cat();
   tree();
   return 0;
}

// Program ends here

Here's the screenshot of the code.

i #include <iostream> using namespace std; // user defined function to print tree void tree() { cout << " * " << endl; cout << " *** " << endl; cout << "* *** " << endl; cout << "* *" << endl; cout << " *** " «< endl; 11 12 13 // user defined function to print cat void cat() { cout << " A A " << endl; cout << " 0 " << endl; cout << " = = " << endl; cout << " -- " << endl; 21 22 int main() { cat(); tree(); return 0; 24

Output of above code:

оо V V

Now, the answer for the second part of the problem. I am adding the code screenshot and the code as well.

Code for B)

// Program begins from here

#include <iostream>
using namespace std;

// a userdefined function to print tree n times
void tree(int n){
   for(int i = 0; i < n; i++)
       cout << "   *    ";
   cout << endl;

   for(int i = 0; i < n; i++)
       cout << " ***   ";
   cout << endl;
  
   for(int i = 0; i < n; i++)
       cout << " ***** ";
   cout << endl;
  
   for(int i = 0; i < n; i++)
       cout << "******* ";
   cout << endl;
  
   for(int i = 0; i < n; i++)
       cout << " ***   ";
   cout << endl;
}

// a userdefined function to print cat n times
void cat(int n){
   for(int i = 0; i < n; i++)
       cout << "/\\   /\\ ";
   cout << endl;

   for(int i = 0; i < n; i++)
       cout << " o o   ";
   cout << endl;
  
   for(int i = 0; i < n; i++)
       cout << " =   = ";
   cout << endl;
  
   for(int i = 0; i < n; i++)
       cout << " ---   ";
   cout << endl;
}

int main(){
   // input variable
   int input;

   // taking input from the user
   cout << "Enter input: ";
   cin >> input;

   // checking if input is even or odd
   if(input % 2 == 0) {
       // if input is even, call tree and cat function 10 times in same line
       cat(10);
       tree(10);
   }
   else {
       // if input is odd, call tree and cat function 20 times in the same column
       for(int i = 1; i <= 20; i++){
           cat(1);
           tree(1);
       }
   }

   return 0;
}

// Program ends here

Here's the screenshot(s) of the code

2 #include <iostream> using namespace std; // a userdefined function to print tree n times void tree(int n) { for(int i = 0; i <n; i++) cout << " * "; cout << endl; for(int i = 0; i<n; i++) cout << " *** " cout << endl; for(int i = 0; i <n; i++) cout << " ***** - cout << endl; for(int i = 0; i <n; i++) cout << "******* "; cout << endl; for(int i = 0; i<n; i++) cout << " *** ". cout << endl;

27 28 // a userdefined function to print cat n times void cat(int n){ for(int i = 0; i <n; i++) cout << " A A "; cout << endl; for(int i = 0; i<n; i++) cout << "00 "; cout << endl; for(int i = 0; i < n; i++) cout << " = = "; cout << endl; i++) for(int i = 0; cout << " cout << endl; i<n; --- # 44 }

46 int main() { // input variable int input; // taking input from the user cout << "Enter input: "; cin >> input; // checking if input is even or odd if(input % 2 == 0){ / if input is even, call tree and cat function 10 times in same line cat(10); tree (10); else { // if input is odd, call tree and cat function 20 times in the same column for(int i = 1; i <= 20; i++){ cat(1); tree(1); 68 69 return 0; }

And output is here: (for even input, because for odd input, the oupt was quite large)

半 半 学学 半 「 半半 半 半 翠翠翠 ¥¥¥¥¥¥ ¥¥¥¥¥¥¥¥¥¥¥¥ ¥¥¥ ¥¥¥ 翠翠翠 羊羊羊 ¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥弟弟弟弟弟弟 ¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥串串 ¥¥ ¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥¥ 羊羊羊羊羊羊羊羊羊羊 羊羊羊羊羊 ¥¥¥ ¥¥¥ ¥¥¥ 早早早 ¥¥¥ 畢著 ¥¥¥ ¥¥¥ ¥¥¥ - || = = = = = = = = = = = = = = = = = = = = oo oo oo oo oo oo oo oo oo oo 1 V V V V V V V V V V V V V V V V V V V VI | b:indul Jalu

I hope this answers your problem.