Question

a sulfuric acid solution containing 551.5

(a) A sulfuric acid solution containing 551.5g of H2SO4 per liter of Solution has a density of 1-339 Icme. Calculate molality of HaSO4 in this solution. the

Answer 1

given

mass of solute H2SO4 = 551.5 g

we have molar mass of H2SO4 =98.079 g/mol

so number of moles of H2SO4 present = given mass/molar mass

= 551.5 g/98.079 g/mol

=5.623 mols***

volume of solution = 1L = 1000 ml

density of solution =1.33 g/cm^3

So mass of solution = volume *density = 1000 cm^3 * 1.33 g/cm^3 = 1330 g

mass of water = 1330 g- 551.5 g= 778.5 g

mass of water in Kg = 0.7785 Kg

molality = number of moles of H2SO4/mass of solvent in Kg = 5.623 mols*/0.7785 Kg

= 7.223 m

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Thank you