"The MAD for the forecast developed using a weighted 2-year moving average with weights of 0.45 and 0.55 = __ miles (round your response to one decimal place). (Hint: You will have only 3 years of matched data.)"

![A 12] 3,100 3,950 3 3,500 3,525 -25 1 Year 2 Mileage 3 Forecast 4 Error 5 Absolute error 5 Weight 7 Weighted moving average o](http://img.homeworklib.com/questions/aff80b00-1a70-11ec-bb02-093e8be7d17e.png?x-oss-process=image/resize,w_560)
In weighted moving average, we determine the forecast as the sum of product of weights and the previous actual mileage. As we have to calculate the MAD, we will have 3 years of matched data or data where both forecast and actual will be available. These would be year 3, 4 and 5.
Forecast for year 3 = 0.55*3950+0.45*3100 = 3567.5.
As actual mileage for year 3 is 3500, absolute error is |3500-3567.5| = 67.5
Forecast for year 4 = 0.55*3500+0.45*3950 = 3702.5
As actual mileage for year 4 is 3850, absolute error is |3850-3702.5| = 147.5
Forecast for year 5 = 0.55*3850+0.45*3500 = 3692.5
As actual mileage for year 5 is 3700, absolute error is |3700-3692.5| = 7.5
Sum of all absolute errors = 67.5+147.5+7.5 = 222.5
Hence MAD = 222.5/3 = 74.2
"The MAD for the forecast developed using a weighted 2-year moving average with weights of 0.45...
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