1. Convert the following statement to a quantified expression, negate it, and convert the answer back to English. You will end up with the exact opposite concept.
All cats are asleep.
2. Convert the following statement into a quantified expression:
Everyone, who has seen Deadpool, likes chimichangas .
3. Simplify the following Quantified Statement. The result should have no negation symbols. ¬ ?x ?x (¬G(x) ? H(x) )
4. Prove the following using induction (show your work- both steps):
If x?2then2+4+6+...+2n = n(n+1)
SOLUTION TO QUESTION 1:
Let C(x) denote that x is a cat and S(x) denote that x is asleep.
Hence, ALL CATS ARE ASLEEP can be written as:
![\forall x [C(x) \rightarrow S(x)]](http://img.homeworklib.com/questions/33e16c10-6dd1-11ec-bbaf-4fc866c30fb9.png?x-oss-process=image/resize,w_560)
The negation of this statement is given as
which is equivalemnt to
which can be interpreted as -
There exists an element x for which x is asleep does not hold. In other words, there is at least a cat which is not asleep.
SOLUTION TO PROBLEM 2:
Everyone, who has seen Deadpool, likes chimichangas.
Assume that D(x) means that x has seen Deadpool and C(x) implies that x like chimichangas. Thus, the above statement can be re-written in quantifier form as:
![\forall x [D(x) \rightarrow C(x)]](http://img.homeworklib.com/questions/35419340-6dd1-11ec-8e8d-519bea9eed49.png?x-oss-process=image/resize,w_560)
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The problem 3 and 4 are beyond understanding. I guess the question replaces some important quantifier/implication condition with ? sign which cannot be interpreted here. I will advise you to re-post these questions with correct conditions.
1. Convert the following statement to a quantified expression, negate it, and convert the answer back...
Problem 1.Write logical expressions in first-order logic for the following sentence: a) Every human has a stomach. b) Everyone is a friend of someone.c) (4 Points) Nobody likes everybody. Problem 2. Negate the following logical statements a) ∀x∃yP(x,y) (Assume that x and y belong to the same domain, and this domain is arbitrary). b)∃x F (x) → ∀y?¬P (y) ∧ ∀zQ(z)? . (Simplify this expression until you have no negation operator).
I need help on b-e. THANK YOU
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