Question

Convert the program you wrote in to an MIPS assembly program. Make sure that you show the symbol table (assume memory is allocated beginning address 5000) and that the equivalent assembly program is commented.

int main() {

int a[10];

int i = 0;

while( i <= 5) {

a[i]=i;

a[9-i]=9-i; i++;

}

Answer 1

MIPS assembly program :

======================

.data
a: .word 0,0,0,0,0,0,0,0,0,0

.text
.globl main

main:
la $s0,a # address location for a(0)
li $t0,0           # int i=0
loop:
bgt $t0,5,done       # loop till i<=5
mul $t2,$t0,4       # calculating offset address
add $s1,$s0,$t2       # address location for a(i)
sw $t0,0($s1)       # a(i)=i
sub $t1,$t0,9       # i-9
mul $t1,$t1,-1       # -(i-9)=9-i
mul $t2,$t1,4       # calculating offset address
add $s1,$s0,$t2       # address loaction for a(9-i)
sw $t2,0($s1)       # a(9-i)=9-i
add $t0,$t0,1       # i++
j loop
done:
  
# exit program
li $v0,10
syscall
====================