If P(A) = 0.25, P(B) = 0.35, and P(A intersection B) = 0.20 then, P(A union...

Question

Question

If P(A) = 0.25, P(B) = 0.35, and P(A intersection B) = 0.20 then, P(A union B) =

math Statistics-And-Probability

Answer 1

Answer #1

P(A union B) = P(A) + P(B) - P(A intersection B)

Substitute given values

=>P(A union B) = P(A) + P(B) - P(A intersection B)

=0.25+0.35 - 0.20

=0.40

Answer 2

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